6.1. Analytic class number formula for h-minus
Let K=\mathbb{Q}(\zeta_p), K^+=\mathbb{Q}(\zeta_p)^+, and n=\frac{p-1}{2}.
Then K has signature (0,n) and K^+ has signature (n,0).
6.1.1. The odd L-product as a residue quotient
The factorisation of the cyclotomic Dedekind zeta function into Dirichlet
L-functions gives \zeta_K(s)=\prod_{\chi \bmod p} L(s,\chi), where the product
runs over all characters modulo p. The even characters are exactly the characters
of \operatorname{Gal}(K^+/\mathbb{Q}), so similarly
\zeta_{K^+}(s)=\prod_{\chi\bmod p,\ \chi\text{ even}} L(s,\chi). Dividing yields
\frac{\zeta_K(s)}{\zeta_{K^+}(s)}=\prod_{\chi\text{ odd}}L(s,\chi).
Since every odd character modulo p is non-trivial, every factor on the right is
holomorphic at s=1. Taking residues at s=1 therefore gives the following.
One has
\prod_{\chi\text{ odd}} L(1,\chi) = \frac{\operatorname*{Res}_{s=1}\zeta_K(s)}{\operatorname*{Res}_{s=1}\zeta_{K^+}(s)}.
Lean code for Proposition6.1.1.1●1 theorem
Associated Lean declarations
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theoremdefined in BernoulliRegular/ZetaFactorisation/Residue.leancomplete
theorem BernoulliRegular.residue_ready_factorization_even_odd.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] : NumberField.dedekindZeta_residue K = (BernoulliRegular.evenLProduct p 1 * BernoulliRegular.oddLProduct p 1).re
theorem BernoulliRegular.residue_ready_factorization_even_odd.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] : NumberField.dedekindZeta_residue K = (BernoulliRegular.evenLProduct p 1 * BernoulliRegular.oddLProduct p 1).re
The quotient \zeta_K(s)/\zeta_{K^+}(s) has a removable singularity at s=1,
because both numerator and denominator have simple poles there. Its value at s=1
is therefore the ratio of the residues. On the other hand this quotient is exactly
the product of the odd Dirichlet L-functions, all of which are regular at s=1.
6.1.2. The relative class number formula
The analytic class number formula gives
\operatorname*{Res}_{s=1}\zeta_F(s) = \frac{2^{r_1(F)}(2\pi)^{r_2(F)}h_F R_F}{w_F\sqrt{|D_F|}}
for every number field F, where R_F is the regulator, w_F the number of
roots of unity, and D_F the discriminant. For the cyclotomic fields under
consideration one uses the standard identities
w_K=2p, \qquad w_{K^+}=2, \qquad R_K = 2^{n-1}R_{K^+}, \qquad |D_K|=p^n|D_{K^+}|.
Combining these with the definition h^- = h_K/h_{K^+} gives the following.
One has
h^- = \frac{2p\,p^{n/2}}{(2\pi)^n}\prod_{\chi\text{ odd}}L(1,\chi).
Proposition 6.1.1.1 Theorem 1.6.4 Definition 1.2.1 Definition 1.2.2 Definition 1.6.3
Lean code for Proposition6.1.2.1●2 theorems
Associated Lean declarations
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theoremdefined in BernoulliRegular/HMinus/ClassNumberFormula.leancomplete
theorem BernoulliRegular.hMinus_formula_via_residues.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : ↑(BernoulliRegular.hMinus K) = NumberField.dedekindZeta_residue K * (↑(NumberField.Units.torsionOrder K) * √|↑(NumberField.discr K)| / (2 ^ NumberField.InfinitePlace.nrRealPlaces K * (2 * Real.pi) ^ NumberField.InfinitePlace.nrComplexPlaces K * NumberField.Units.regulator K)) / (NumberField.dedekindZeta_residue ↥(NumberField.maximalRealSubfield K) * (↑(NumberField.Units.torsionOrder ↥(NumberField.maximalRealSubfield K)) * √|↑(NumberField.discr ↥(NumberField.maximalRealSubfield K))| / (2 ^ NumberField.InfinitePlace.nrRealPlaces ↥(NumberField.maximalRealSubfield K) * (2 * Real.pi) ^ NumberField.InfinitePlace.nrComplexPlaces ↥(NumberField.maximalRealSubfield K) * NumberField.Units.regulator ↥(NumberField.maximalRealSubfield K))))
theorem BernoulliRegular.hMinus_formula_via_residues.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : ↑(BernoulliRegular.hMinus K) = NumberField.dedekindZeta_residue K * (↑(NumberField.Units.torsionOrder K) * √|↑(NumberField.discr K)| / (2 ^ NumberField.InfinitePlace.nrRealPlaces K * (2 * Real.pi) ^ NumberField.InfinitePlace.nrComplexPlaces K * NumberField.Units.regulator K)) / (NumberField.dedekindZeta_residue ↥(NumberField.maximalRealSubfield K) * (↑(NumberField.Units.torsionOrder ↥(NumberField.maximalRealSubfield K)) * √|↑(NumberField.discr ↥(NumberField.maximalRealSubfield K))| / (2 ^ NumberField.InfinitePlace.nrRealPlaces ↥(NumberField.maximalRealSubfield K) * (2 * Real.pi) ^ NumberField.InfinitePlace.nrComplexPlaces ↥(NumberField.maximalRealSubfield K) * NumberField.Units.regulator ↥(NumberField.maximalRealSubfield K))))
Rearranging the analytic class number formulas for `K` and `K⁺` gives a relative residue expression for `h⁻`. This isolates the remaining analytic input needed for Theorem 43 to the identification of the `K⁺`-side residue with the even-character product.
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theoremdefined in BernoulliRegular/HMinus/LValueReduction/Final.leancomplete
theorem BernoulliRegular.hMinus_formula_of_residue_and_hPlus_cyclotomic_and_gauss.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) (hres : ↑(NumberField.dedekindZeta_residue K) = (∏ χ ∈ BernoulliRegular.evenNontrivialCharacters p, BernoulliRegular.evenLValueRhs p χ) * ∏ χ ∈ BernoulliRegular.oddCharacters p, DirichletCharacter.LFunction χ 1) (hplus : ↑(BernoulliRegular.hPlus K) = BernoulliRegular.cyclotomicHPlusFactor K * ∏ χ ∈ BernoulliRegular.evenNontrivialCharacters p, BernoulliRegular.evenLValueRhs p χ) (hgauss : BernoulliRegular.cyclotomicHGaussGoal p K) : ↑(BernoulliRegular.hMinus K) = 2 * ↑p * ∏ χ ∈ BernoulliRegular.oddCharacters p, -(1 / 2) * BernoulliRegular.BernoulliGen χ⁻¹ 1
theorem BernoulliRegular.hMinus_formula_of_residue_and_hPlus_cyclotomic_and_gauss.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) (hres : ↑(NumberField.dedekindZeta_residue K) = (∏ χ ∈ BernoulliRegular.evenNontrivialCharacters p, BernoulliRegular.evenLValueRhs p χ) * ∏ χ ∈ BernoulliRegular.oddCharacters p, DirichletCharacter.LFunction χ 1) (hplus : ↑(BernoulliRegular.hPlus K) = BernoulliRegular.cyclotomicHPlusFactor K * ∏ χ ∈ BernoulliRegular.evenNontrivialCharacters p, BernoulliRegular.evenLValueRhs p χ) (hgauss : BernoulliRegular.cyclotomicHGaussGoal p K) : ↑(BernoulliRegular.hMinus K) = 2 * ↑p * ∏ χ ∈ BernoulliRegular.oddCharacters p, -(1 / 2) * BernoulliRegular.BernoulliGen χ⁻¹ 1
Applying the analytic class number formula to K and K^+ gives
h_K = \operatorname*{Res}_{s=1}\zeta_K(s)\cdot \frac{w_K\sqrt{|D_K|}}{(2\pi)^n R_K}
and
h_{K^+} = \operatorname*{Res}_{s=1}\zeta_{K^+}(s)\cdot \frac{w_{K^+}\sqrt{|D_{K^+}|}}{2^n R_{K^+}}.
Taking the quotient,
h^- = \frac{\operatorname*{Res}_{s=1}\zeta_K(s)}{\operatorname*{Res}_{s=1}\zeta_{K^+}(s)} \cdot \frac{w_K}{w_{K^+}} \cdot \frac{2^n R_{K^+}}{(2\pi)^n R_K} \cdot \sqrt{\frac{|D_K|}{|D_{K^+}|}}.
Substituting the four identities above gives
h^- = \frac{2p\,p^{n/2}}{(2\pi)^n} \frac{\operatorname*{Res}_{s=1}\zeta_K(s)}{\operatorname*{Res}_{s=1}\zeta_{K^+}(s)}.
Now apply Proposition 6.1.1.1.
6.1.3. The product of the odd Gauss sums
For a primitive character \chi modulo p, write
\tau(\chi)=\sum_{a\in \mathbb{Z}/p\mathbb{Z}}\chi(a)e^{2\pi i a/p}. The standard
identity \tau(\chi)\tau(\chi^{-1}) = \chi(-1)p shows that each inverse pair of odd
characters contributes -p to the product of all odd Gauss sums.
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BernoulliRegular.rawGaussProduct[complete] -
BernoulliRegular.cyclotomicHGaussGoal_holds[complete]
One has \prod_{\chi\text{ odd}} \tau(\chi) = i^n p^{n/2}.
Lean code for Lemma6.1.3.1●2 theorems
Associated Lean declarations
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BernoulliRegular.rawGaussProduct[complete]
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BernoulliRegular.cyclotomicHGaussGoal_holds[complete]
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BernoulliRegular.rawGaussProduct[complete] -
BernoulliRegular.cyclotomicHGaussGoal_holds[complete]
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theoremdefined in BernoulliRegular/HMinus/LValueReduction/GaussProduct.leancomplete
theorem BernoulliRegular.rawGaussProduct (p : ℕ) [hp : Fact (Nat.Prime p)] (hp_odd' : p ≠ 2) : ∏ χ ∈ BernoulliRegular.oddCharacters p, gaussSum χ ZMod.stdAddChar = Complex.I ^ ((p - 1) / 2) * ↑√(↑p ^ ((p - 1) / 2))
theorem BernoulliRegular.rawGaussProduct (p : ℕ) [hp : Fact (Nat.Prime p)] (hp_odd' : p ≠ 2) : ∏ χ ∈ BernoulliRegular.oddCharacters p, gaussSum χ ZMod.stdAddChar = Complex.I ^ ((p - 1) / 2) * ↑√(↑p ^ ((p - 1) / 2))
**T023d6**: Merge the two `mod 4` branches into the clean raw odd Gauss-product formula used downstream.
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theoremdefined in BernoulliRegular/HMinus/LValueReduction/GaussProduct.leancomplete
theorem BernoulliRegular.cyclotomicHGaussGoal_holds.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : BernoulliRegular.cyclotomicHGaussGoal p K
theorem BernoulliRegular.cyclotomicHGaussGoal_holds.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : BernoulliRegular.cyclotomicHGaussGoal p K
**T023d7**: Package the raw odd Gauss-product formula as the exact cyclotomic `hgauss` hypothesis consumed by the final `hMinus` assembly theorem.
If p\equiv 1\pmod 4, then the quadratic character is even, so no odd character is
self-inverse. The odd characters split into n/2 inverse pairs, each contributing
-p. Therefore \prod_{\chi\text{ odd}}\tau(\chi)=(-p)^{n/2}=i^n p^{n/2}.
If p\equiv 3\pmod 4, then the quadratic character \lambda is odd and is the
unique self-inverse odd character. The remaining odd characters split into
(n-1)/2 inverse pairs, so
\prod_{\chi\text{ odd}}\tau(\chi) = \tau(\lambda)(-p)^{(n-1)/2}. The classical
quadratic Gauss sum evaluation gives \tau(\lambda)=i\sqrt p. Hence
\prod_{\chi\text{ odd}}\tau(\chi) = i\sqrt p\,(-p)^{(n-1)/2} = i^n p^{n/2}.
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BernoulliRegular.hMinus_formula[complete]
Analytic formula for \hminus. The relative class number satisfies
h^- = 2p\prod_{\chi\text{ odd}} \left(-\frac12\,B_{1,\chi^{-1}}\right).
Proposition 6.1.2.1 Corollary 5.2.2 Lemma 6.1.3.1 Definition 3.1.1
Lean code for Theorem6.1.3.2●1 theorem
Associated Lean declarations
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BernoulliRegular.hMinus_formula[complete]
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BernoulliRegular.hMinus_formula[complete]
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theoremdefined in BernoulliRegular/HMinus/LValueReduction/Final.leancomplete
theorem BernoulliRegular.hMinus_formula.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : ↑(BernoulliRegular.hMinus K) = 2 * ↑p * ∏ χ ∈ BernoulliRegular.oddCharacters p, -(1 / 2) * BernoulliRegular.BernoulliGen χ⁻¹ 1
theorem BernoulliRegular.hMinus_formula.{u_1} (p : ℕ) [hp : Fact (Nat.Prime p)] (K : Type u_1) [Field K] [NumberField K] [IsCyclotomicExtension {p} ℚ K] [NumberField.IsCMField K] (hp_odd' : p ≠ 2) : ↑(BernoulliRegular.hMinus K) = 2 * ↑p * ∏ χ ∈ BernoulliRegular.oddCharacters p, -(1 / 2) * BernoulliRegular.BernoulliGen χ⁻¹ 1
Diekmann Theorem 43: the relative class number of a cyclotomic field of prime conductor is the odd-character Bernoulli product. This is the explicit statement ultimately obtained by combining the cyclotomic class-number formula with the odd and even `L(1, χ)` evaluations.
There are exactly n=(p-1)/2 odd characters modulo p. By
Proposition 6.1.2.1,
h^- = \frac{2p\,p^{n/2}}{(2\pi)^n} \prod_{\chi\text{ odd}}L(1,\chi). For each odd
character \chi, Corollary 5.2.2 gives
L(1,\chi)=\frac{\pi i\,\tau(\chi)}{p}\,B_{1,\chi^{-1}}. Multiplying over all odd
characters yields
\prod_{\chi\text{ odd}}L(1,\chi) = \left(\frac{\pi i}{p}\right)^n \left(\prod_{\chi\text{ odd}}\tau(\chi)\right) \left(\prod_{\chi\text{ odd}}B_{1,\chi^{-1}}\right).
By Lemma 6.1.3.1, this becomes
\prod_{\chi\text{ odd}}L(1,\chi) = \frac{\pi^n i^{2n}}{p^{n/2}} \prod_{\chi\text{ odd}}B_{1,\chi^{-1}} = \frac{\pi^n(-1)^n}{p^{n/2}} \prod_{\chi\text{ odd}}B_{1,\chi^{-1}}.
Substituting back gives
h^- = \frac{2p\,p^{n/2}}{(2\pi)^n} \cdot \frac{\pi^n(-1)^n}{p^{n/2}} \prod_{\chi\text{ odd}}B_{1,\chi^{-1}} = 2p\left(-\frac12\right)^n \prod_{\chi\text{ odd}}B_{1,\chi^{-1}}.
Since there are exactly n odd characters, this is precisely
2p\prod_{\chi\text{ odd}} \left(-\frac12\,B_{1,\chi^{-1}}\right).